2/4-x^2-1/2x-4-7/2x^2+4x=0

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Solution for 2/4-x^2-1/2x-4-7/2x^2+4x=0 equation: 


x in (-oo:+oo)

4*x-x^2-((7/2)*x^2)-((1/2)*x)+2/4-4 = 0

(-7/2)*x^2-x^2+(-1/2)*x+4*x+2/4-4 = 0

7/2*x-9/2*x^2-7/2 = 0

DELTA = (7/2)^2-(-9/2*(-7/2)*4)

DELTA = -203/4

DELTA < 0

x belongs to the empty set

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